Question

All the jacks, queens and kings are removed from a deck of 52 playing cards. The remaining cards are well shuffled and then one card is drawn at random. Giving 'ace' a value 1, similar value for other cards, find the probability that the card has a value ...

1) 7

2) greater than 7

3) less than 7

Answer 1

We know that total number of cards = 52.

There are 4  jack.

There are 4 queens.

There are 4 kings.


Given that All the jacks, queens and kings are removed from the deck.

52 - (4 + 4 + 4)

52 - 12

40 cards are left.



Given that one card is drawn, giving ace a value 1.

The number of aces = 4.

Now,

(1) The probability that the other card has a value 7:

P(A) = 4/40

        = 1/10.



(2) The probability that the card has a value greater than 7:

P(B) = 12/40

        = 3/10



(3) The probability that the card has value lesser than 7:

P(C) = 24/40

        = 3/5.


Hope this helps!