Question

All the lines whose sum of reciprocal of
intercepts is k will be concurrent at the
point​

Answer 1

Given: Some particular lines.

To find: All the lines whose sum of reciprocal of  intercepts is k will be concurrent at the  point​.

Solution:

• Consider the equation of a line as:

                    x/a + y/b  = 1

• The intercepts are a and b on x and y axes.

• According to the question, we have:

                    1/a + 1/b = k

                    1/ak + 1/bk = 1

                    (1/k)/a + (1/k)/b = 1

• So here 1/k is satisfying the equation x/a + y/b  = 1.

• So the points are: (1/k , 1/k).

Answer:

               So all the lines whose sum of reciprocal of  intercepts is k will be concurrent at the  point is (1/k , 1/k).

Answer 2

Answer

Step-by-step explanation:see the attached below