all the points equidistant from the given two points A and B lie on the __________ of the line segment AB
Answers
PERPENDICULAR BISECTOR
Step-by-step explanation:
all the points equidistant from the given two points A and B lie on the PERPENDICULAR BISECTOR of the line segment AB
Proof :
Let say AB is the line Segment
XY is the perpendicular Bisector interesecting AB at O
=> AO = BO
∠AOX = ∠AOY = ∠BOX = ∠BOY = 90°
Lets take any point P on XY
Comparing Δ AOP & ΔBOP
AO = BO
∠AOP = ∠BOP = 90°
OP = OP ( common)
=> Δ AOP ≅ ΔBOP
=> AP = BP
Hence all the points equidistant from the given two points A and B lie on the perpendicular bisector of the line segment AB
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Answer:
Perpendicular bisector