all the surfaces shown in figure are assumed to be frictonless. the block of mass m slides on the prism which in turn slides backward on the horizontal surface. find the acceleration of the smaller block with respect to the prism
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Answer:
Let reaction between prism and block= N,
Acceleration of prism w.r.t ground= A
Acceleration of block w.r.t prism= ar
Explanation:
Firstly equate forces on prism.
Nsinθ=MA −−−−−−−−−−(1)
now, forces on block,
mar==mgsinθ + mAcosθ −−−−−−−−−−−(2)
N=mgcosθ − mAsinθ −−−−−−−−−−−(3)
On solving eq (1),(2) and (3) we will get
ar =gsinθ[M+m/M+msin2θ]
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