All the theorems in triangle chapter in maths of class 10th
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Given: In △ABC,D and E are midpoints of AB and AC respectively,
i.e., AD=DB and AE=EC
To Prove: DE∥BC
Proof:
Since, AD=DB
∴
DB
AD
=1............(1)
Also,
AE=EC
∴
EC
AE
=1............(2)
From (1) and (2),
DB
AD
=
EC
AE
=1
i.e.,
DB
AD
=
EC
AE
∴ By converse of Basic Proportionality theorem,
DE∥BC
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