Question

All the values of k for which the quadratic polynomial S(x) = -2° + kr+k+s has two distinct zeroes and only one of them satisfying
0

Answer 1

Answer:

a+10b=-3+10=7

Step-by-step explanation:

for two distinct roots,D>0 i.e.,k2 +8(k2 +5)> 0 which is always true. also let f(x) =2x2+kx +k2+5=0. I think this is the ryt ans.