all the vertices of a rhombus lie on a circle. find the area of the rhombus if the area of the circle is 1256cm2
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11
Solution :
Area of the circle is
πr^2 = 1256
=> r^2 = 1256/3.14
=> r^2 = 400
∴r=20
Hence the diameter = 2r = 40
Since all the vertices lie on the circle, the diameter of the circle is the diagonal of the Rhombus.
since both the diagonals are equal , it is a square.
Hence the area of the rhombus is 1/2 x d1 x d2
= 1/2 x 20 x 20
= 200 cm^2
Area of the circle is
πr^2 = 1256
=> r^2 = 1256/3.14
=> r^2 = 400
∴r=20
Hence the diameter = 2r = 40
Since all the vertices lie on the circle, the diameter of the circle is the diagonal of the Rhombus.
since both the diagonals are equal , it is a square.
Hence the area of the rhombus is 1/2 x d1 x d2
= 1/2 x 20 x 20
= 200 cm^2
Answered by
1
Answer:
Diameter is =20 therefore 1/2 * base*height= 1/2*20*20=200
Step-by-step explanation:
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