All three vertices of triangle ABC lie on the parabola defined by y=x^2, with A at the origin and {BC} parallel to the x-axis. The area of the triangle is 64. What is the length of BC?
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when you plot the graph,it is at (-x,x^2)and (x,x^2) is iscosceles
when you set up the triangle it is=64*1/2*2x*x^2=64=x^3
x=4 then 2x=8
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