Question

All triangles in the figure are equilateral triangles. Find <ACF​

Answer 1

Answer:

Since each of the ∆ABC and ∆ACF is an equilateral triangle, so each angle of his strength is one of them is 60°. So, the angles are equiangular, and hence similar. => ∆BCE ~ ∆ACF. We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.