Math, asked by Anonymous, 4 months ago

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A group of Singaporean students studying in the United Kingdom travels from the United Kingdom to France.They exchange a certain amount of sterling pounds (£) to euros (€) at a rate of £100 = €115.
They rent a car in France to travel 1850 km. One litre of petrol allows the car to travel 12 km and each litre.
of petrol costs €0.80. On top of the amount which they spend on petrol, they spend a total of €3500 in France, including the car rental. They convert the remaining euros into sterling pounds at the end of the trip at a rate of £100 - €116.50. Given that they receive £75, find the amount of sterling pounds that they exchange before going on their trip,giving your answer correct to the nearest pound.

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Answers

Answered by poojachoudhary40
0

Answer:

"allows" (and any subsequent words) was ignored because we limit queries to 32 words.

Answered by satwik6460
0

Answer:

Numerator of rational number is 4 less than its denominator.

If 1 added to both is numerator and denominator the fraction before ½.

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To find:

Fraction?

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Solution:

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☯ Let the Denominator of a rational be x.

Then, numerator = (x - 4)

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\begin{gathered}\bigstar\:{\underline{\sf{According\:to\:the\:question\::}}}\\ \\\end{gathered}

Accordingtothequestion:

If 1 added to both is numerator and denominator the fraction before ½.

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\begin{gathered}:\implies\sf \dfrac{(x - 4) + 1}{x + 1} = \dfrac{1}{2}\\ \\\end{gathered}

:⟹

x+1

(x−4)+1

=

2

1

\begin{gathered}:\implies\sf \dfrac{x - 3}{x + 1} = \dfrac{1}{2}\\ \\\end{gathered}

:⟹

x+1

x−3

=

2

1

\begin{gathered}:\implies\sf 2(x - 3) = x + 1\\ \\\end{gathered}

:⟹2(x−3)=x+1

\begin{gathered}:\implies\sf 2x - 6 = x + 1\\ \\\end{gathered}

:⟹2x−6=x+1

\begin{gathered}:\implies\sf 2x - x = 1 + 6\\ \\\end{gathered}

:⟹2x−x=1+6

\begin{gathered}:\implies{\underline{\boxed{\sf{\purple{x = 7}}}}}\;\bigstar\\ \\\end{gathered}

:⟹

x=7

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Therefore,

⠀⠀⠀

Denominator of rational number, x = 7

Numerator of rational number, (x - 4) = 7 - 4 = 3

\therefore\;{\underline{\sf{The\; required\;rational\;number\;is\; \bf{\dfrac{3}{7}}.}}}∴

Therequiredrationalnumberis

7

3

.

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