Math, asked by pasalasampath07, 5 hours ago

all Zeroes
find of
two of its
Jeroes
are de and are

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Answered by Diliptalapda
1

Answer:

 \implies \:  \:  \:  \: 2( \sqrt{2} ) ^{4}  -  {3( \sqrt{2} )}^{3}  - 3( \sqrt{2} ) ^{2}  + 6( \sqrt{2} ) - 2

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