Question

All zeroes of f (x)=x^3+13x^2+32x+20​

Answer 1

Answer:

(-1)

Step-by-step explanation:

f(-1)=

${ - 1}^{3} + 13 { - 1}^{2} + 32( - 1) + 20 = - 1 + 13 - 32 + 20 = 0$