alligation or mixture problem, plz help
A jar full of whisky contains 40% of alcohol.A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26 the quantity of whisky replaced is
a. 2/5
b 1/3
c 2/3
d 3/5
explain?
Answers
Answered by
1
hey
Here is your answer,
Let us assume the total original amount of whiskey = 10 ml ---> 4 ml alcohol and 6 ml non-alcohol.
Let x ml be the amount removed ---> total alcohol left = 4-0.4x
New quantity of whiskey added = x ml out of which 0.19 is the alcohol.
Thus, the final quantity of alcohol = 4-0.4x+0.19x ----> (4-0.21x)/ 10 = 0.26 ---> x = 20/3 ml.
Per the question, you need to find the x ml removed as a ratio of the initial volume ---> (20/3)/10 = 2/3.
Hence, C is the correct answer.
Hope it helps you!
Here is your answer,
Let us assume the total original amount of whiskey = 10 ml ---> 4 ml alcohol and 6 ml non-alcohol.
Let x ml be the amount removed ---> total alcohol left = 4-0.4x
New quantity of whiskey added = x ml out of which 0.19 is the alcohol.
Thus, the final quantity of alcohol = 4-0.4x+0.19x ----> (4-0.21x)/ 10 = 0.26 ---> x = 20/3 ml.
Per the question, you need to find the x ml removed as a ratio of the initial volume ---> (20/3)/10 = 2/3.
Hence, C is the correct answer.
Hope it helps you!
Seikh1:
what
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