Allo.
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8. What is the sum of the first 10 terms of an A.P. 41, 36, 31, 26, ...?
+ (A) 635 (B) 600 (C) 200 (D) 185
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A.P -----> 41, 36, 31, 26, ...........
So, First term = a = 41
d = 36 - 41 = - 5
n = 10
We know,
Sn = a + ( n - 1 ) d
S10 = 41 + ( 10 - 1 ) * (-5)
S10 = 41 + ( - 45 )
S10 = - 4
Answered by
9
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