Question

Alloy a contains 40% gold and 60% silver. alloy b contains 35% gold and 40% silver and 25% copper. alloys a and b are mixed in the ratio of 1:4 .what is the percentage of gold and silver in the newly formed alloy is?

Answer 1

Given Alloys a and b are mixed in the ratio of 1: 4

Let the weight of alloy A be 1000 kg

Then quantity of Gold in alloy A = 1000kg @ 40% = 400kg

Quantity of silver in alloy A = 1000kg @ 60% = 600kg

Since the ratio is 1:4

Alloy B will be 4000 Kg

the quantity of Gold in alloy B= 4000kg @35%= 1400kg

the quantity of silver in alloy B = 4000 @40% = 1600kg

the quantity of copper in the alloy B = 4000@25%= 1000kg


So total quantity of Gold in the mixture of alloy A and alloy B is 400 kg + 1400kg = 1800kg

Total quantity of silver in the mixture of alloy A and alloy B is 600kg + 1600kg = 2200kg

Total quantity of copper in the mixture of alloy A and alloy B= 1000kg

Total weight of mixture of Alloy A and alloy B = 1000kg + 4000kg = 5000kg..

Total of Gold and silver when put Together = 1800 + 2200 kg = 4000 Kg

the of Gold and silver Together in the newly formed mixture is 4000/5000 = 80%

Individually Gold = 1800/5000 = 0.36 or 36%

Individually silver= 2200/5000= 0.44 or 44%

Answer 2

hi
the percantage of gold is 36%
the percantage of silver is 44%