Question

alloy X contains 20% of zinc and alloy Y contains 40% zinc if a new alloy Z is made by mixing alloy X and alloy Z and proportion of X and Y is 2:1 what is the concentration of zinc in the new alloy Z.

Indicate all such values
a) 18%
b) 20%
c) 22%
d) 25%
e) 26%
f) 28%

Answer 1

Option e) 26% is the concentration of zinc in alloy Z.

Step-by-step explanation:

Alloy X contains 20% of zinc and alloy Y contains 40% zinc.

New alloy Z is made by alloy X and alloy Y in the proportion = 2 : 1

Let the quantity of alloy be 200 g. + 100 g = 300 grams

Quantity of zinc in alloy Z = 20% of 200 + 40% of 100

                                          = $\frac{20\times 200}{100} +\frac{40\times 100}{100}$

                                          = 40 + 40

                                          = 80 grams

In 300 grams of alloy Z the quantity of zinc  = $\frac{80}{300}\times 100$

                                                                         = 26.66%

Option e) 26% is the value of zinc in alloy Z.

Learn more ratio problem : https://brainly.in/question/14671963

Answer 2

The concentration of zinc in the new alloy is 26%

• alloy X contains 20% of zinc

• alloy Y contains 40% of zinc

• new alloy z is formed in which 2 parts are X and 1 part is Y

• So in 300 parts of the alloy Z,

20+20 = 40 is zinc from alloy X

40 is zinc from alloy Y

• So total zinc is 80

• The concentration of zinc in the new alloy Z is

80/300

8/30

4/15

= 26.667

≈ 26