Question

Allrounder Pump Options 75 At Coding Ninjos, we have on allrounder pump. The pump can be used to empty the tant es we lose to the tack The emptying power of the pump is 15 m min higher than filling power. Because of greater emptying power, it takes & minutes lesser to empty the tank than it needs to fill Can you tell us the emptying power of the pump, if the capacity of the tank is 2400 m3 Note: The options are given in the units of m^3/min.

75
65
85
55​

Answer 1

Answer:

75

Step-by-step explanation:

Answer 2

Answer:

75

Step-by-step explanation:

Let the filling capacity of the pump $=x m^3/min.$

Then the emptying capacity of the pump$=(x+10) m^3/min.$

Time required for filling the tank $=\dfrac{2400}{x}$ minutes.

Time required for emptying the tank $=\dfrac{2400}{x+15}$ minutes.

The pump needs 15 minutes lasser to empty the tank than it needs to fill it.

$\Rightarrow \dfrac{2400}{x}-\dfrac{2400}{x+15}=8\\\\\\\Rightarrow \dfrac{300}{x}-\dfrac{300}{x+15}=1\\\\\\\Rightarrow 300(x+15)-300x=x(x+15)\\\\\\\Rightarrow 4500=x^2+15x\\\\\\\Rightarrow x^2+15x-4500=0\\\\\\\Rightarrow (x+75)(x-60)=0\\\\\\\Rightarrow x=60\text{ or }-75$

Since x can not be negative, x=60

Hence., emptying power of the pump =60+15= 75m3/min.