Question

AllS. 200JJ
A marble of mass 2m travelling at 6
cm/s is directly followed by another
marble of mass m with double speed.
After collision, the heavier one travels
with the average initial speed of the two.
Calculate the coefficient of restitution.​

Answer 1

Answer:

1/2

Explanation:

m1 = 2m , u1=6 ,v1 = 9,m2 = m, u2= 12 v1 = [(m1-em2)u1+(m2+em2)u2]/m1+m2