Physics, asked by gunjan1260, 11 months ago

ALLYA heat flux of 4000 J/s is to be passed through àcopper rod of length 10 cm and area of cross section100 cm2. The thermal conductivity of copper is 400W/m°C. The two ends of this rod must be kept at atemperature difference of4

Answers

Answered by AbdJr10

0

Answer:

by tempt diff of 409

Explanation:

dq/dt = kAdt/L

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