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Answered by
5
Hi ,
*****************************************
We know that ,
cos 45° = 1/√2 ;
sec 30° = 2/√3 ;
cosec 30° = 2/1 ;
*******************************************
Now ,
cos45°/( sec 30° + cosec 30° )
= ( 1/√2 )/[ 2/√3 + 2/1 ]
= ( 1/√2 )/ [2 ( 1 + √3 )/√3 ]
= ( 1/√2 )× ( √3/2 ) × 1/( 1 + √3 )
= [ √3( √3 - 1 )]/[2√2 (√3 + 1)(√3-1)]
= [ (3-√3)]/[2√2 ×2 ]
= (3-√3)/4√2
I hope this helps you.
: )
*****************************************
We know that ,
cos 45° = 1/√2 ;
sec 30° = 2/√3 ;
cosec 30° = 2/1 ;
*******************************************
Now ,
cos45°/( sec 30° + cosec 30° )
= ( 1/√2 )/[ 2/√3 + 2/1 ]
= ( 1/√2 )/ [2 ( 1 + √3 )/√3 ]
= ( 1/√2 )× ( √3/2 ) × 1/( 1 + √3 )
= [ √3( √3 - 1 )]/[2√2 (√3 + 1)(√3-1)]
= [ (3-√3)]/[2√2 ×2 ]
= (3-√3)/4√2
I hope this helps you.
: )
FuturePoet:
Great !!!!!!!!!!!
Answered by
3
Cos 45°= 1/√2
sec 30° = 1/cos 30° = 2/√3
cosec 30° = 1/sin 30° = 2
Now
cos 45°/(sec 30° + cosec 30°)
=(1/√2) / [(2/√3) + 2]
=(1/√2) / [(2+2√3) /√3]
=(1/√2) * [√3/(2+2√3)]
=√3 /√2(2+2√3)
;)
Hope it helps
sec 30° = 1/cos 30° = 2/√3
cosec 30° = 1/sin 30° = 2
Now
cos 45°/(sec 30° + cosec 30°)
=(1/√2) / [(2/√3) + 2]
=(1/√2) / [(2+2√3) /√3]
=(1/√2) * [√3/(2+2√3)]
=√3 /√2(2+2√3)
;)
Hope it helps
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