Question

aloha users!!
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*CONTENT QUALITY*
NO COPYING!!

don't answer if u don't know!
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thanks in advance.

Answer 1

Let the distance traveled by the car in 6seconds=AB=X metres
Height of the tower CD=h metres
The remaining distance to be traveled by the car BC =d metres
AC =AB+BC=x+d metres
ANGLE PDA=ANGLE DAC=30
ANGLE PDB=ANGLE DB*C=60

TRIANGLE BCD TAN60=CD/BC=root3=h/d
h=root3d
TRIANGLE ACD TAN30=CD/AC
1/root3=h/(x+d)
h=(x+d)/root3
(x+d)/root3=root3d
x+d=3d
x=2d
d=x/2
Time taken to travel x metres =6seconds
Time taken to travel the distance of D metres i. e., x/2=6/2=3seconds

Answer 2

hope this helps you...