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a light incident at an interface at an angle of 60 degree is refracted into another medium at an angle of 30 degree. if its speed in the 1st medium is c, then its speed in second medium is what? explain how.
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By snells law,
2n1=sin1/sin2
Where 2n1=refractive index of second medium
Sin1 = sin of angle 1=sin 60=root3/2
Sin2=sin of angle 2=sin30= 1/root2
There fore, 2n1=0.867/0.707=1.23
Let 2n1 =N
Therefore
N = c/v
C =speed of light in vacuum = 3×10^8
There fore
V = c /N
= 3×10^8/1.23
= 2.49 ×10^8 Ans...
Hope this helps you....
Plz mark it as brainliest...
2n1=sin1/sin2
Where 2n1=refractive index of second medium
Sin1 = sin of angle 1=sin 60=root3/2
Sin2=sin of angle 2=sin30= 1/root2
There fore, 2n1=0.867/0.707=1.23
Let 2n1 =N
Therefore
N = c/v
C =speed of light in vacuum = 3×10^8
There fore
V = c /N
= 3×10^8/1.23
= 2.49 ×10^8 Ans...
Hope this helps you....
Plz mark it as brainliest...
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