alok has 3 times as much money as riya ,riya has rs.200 less than madhav has rs.50 more than alok .If total amount of money they have is rs.575 .Find names each has
Answers
Step-by-step explanation:
Let money with Alok= ₹x
Money with Madhav= x+50
Mone with Riya = x+50-200
Total Money = 575
Sum of Alok, Madhav and Riya = total money
X + X + 50 + X + 50 - 200 = 575
3x + 100 - 200 = 575
3x -100 = 575
3X = 575 +100
3x = 675
X = 675/3
X= 225
Money with Alok = ₹225
Money with Madhav = ₹ 225+50
= ₹275
Money with Riya = ₹275 - 200
= ₹75
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Answer:
hey , mate
Step-by-step explanation:
let money with Alok be x, riya be y and madhav be z.
so, by condition
x=3y ----1
y=z-200 -----2
z= x+50 -----3
Substitute 1 in 3
we get,
z= 3y+50 ----4
eq 2 can be written as z = y+200 ----5
solving eq 4 and 5 by elimination or substitution method we get,
z= 3y+50
3z=3y+ 600
solving equations for z and y
z=275 , y= 75
substitute the value of y in eq 1
we get, x = 225
Alok has rs. 225
Riya has rs.75
Madhav has rs.275
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