Question

Alok's age is four times his son's age. Eight
years ago, he was twelve times his son's age.
Find their present ages.​

Answer 1

Answer:

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Step-by-step explanation:

Let his son be x now

Alok will be 4x now

8 years ago,

His son = x - 8

Alok = 4x - 8

8 years go, Alok is 12 times his son's age:

4x - 8 = 12(x - 8)

Solve for x:

4x - 8 = 12(x - 8)

4x - 8 = 12x - 96

12x - 4x = 96 - 8

8x = 88

x = 11

His son = x = 11 years old

Alok = 4x = 11 x 4 = 44 years old

Answer: Alok is 44 years old and his son is 11 years old

Answer 2

Step-by-step explanation:

Let the present age of his son be x years old.

Then, Alok's age = 4x.

Eight years ago,

Alok age = (4x-8)

Son age = (x-8)

According to the question :

(4x-8) = 12 (x-8)

4x - 8 = 12x - 96

12x - 4x = 96-8

8x = 88

x = 11 .

therefore, Son is 11 years old and Alok is (4x) = 44 years old.