Question

alone.
25. A can do a piece of work in 9 days. B is 50% more efficient than A. How
many days will B alone take to complete the same piece of work?
da Both​

Answer 1

Let total work to be done=1

Then, A's one day work= (total work) / (total days taken by A) =1/9

B's one day work= 150% of A's one day work (because B is 50% more efficient)

=(1/9)*(150/100)=1/6

Total time taken by B to do total work=

(1/6)

1

=6 I hope it's help you ❤️☺️