Question

Along a straight road, if a car accelerates at 2.5 m/s2, how much is its increase in velocity in 4s? (a) 6m/s (b) 2m/s (c) 10 m/s (d) 2.66 m/s​

Answer 1

Answer: 10 m/s

Explanation:

$a=\frac{v-u}{t}$

At the beginning, the car is at its instantaneous acceleration. So, we have to conclude that increase in its velocity is equal to the difference in their relative velocities at 0 sec and 4 sec.

$2.5=\frac{v-u}{4} \\v-u=10$

Hence the initial velocity has increased by 10 m/s .

Answer 2

Answer:

The answer is - option (c)

10.0 m/s or 10 m/s

Explanation:

To find how much the velocity increase in 4s when, if a car along a straight road accelerates at 2.5 m/$s^{2}$

Follow the formula of acceleration

As we know that acceleration = $\frac{v - u}{t}$,  where $v - u$ = [In scientific terms = final velocity - initial velocity] increase or decrease of the velocity in a given time and t symbolizes time taken

So,

Acceleration of the car = 2.5 m/$s^{2}$ [Given]

Time taken or $t$ = 4s [Given]

ACCELERATION = $\frac{v - u}{t}$

2.5 = $\frac{v - u}{4}$

$v - u$ or increase in velocity = 2.5 X 4 [Using  Cross multiplication]

Increase in velocity = 10.0 m/s or 10 m/s [Option (c)]

HOPE THE ANSWER WILL BE A GREAT PATH OF LEARNING, FRIENDLY

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