Question

Alpha=2 beta=3 find the polynomial whoes zeroes are given as under

Answer 1

Answer:x^2+6x+3

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Secondary School Math 5+3 pts

If alpha =2, beta =3 are zeroes of polynomial x2-5x +6 then find the polynomial whose zeroes are 1 divide alpha and 1 divide beta

by VishnurajD 06.04.2018

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Answers

Panzer786

Panzer786Maths AryaBhatta

Hii friend,

P(X) = X²-5X+6

Alpha = 2

Betaine = 3

Therefore,

1/Alpha = 1/2

And,

1/Beta = 1/3

Alpha+Beta = 1/2+1/3 = 3+2/6 = 5/6

Alpha×Beta = 1/2×1/3 = 1/6

Therefore,

Quadratic polynomial = X²-(Alpha+Beta)X+ Alpha × Beta. = X²-(5/6)X+1/6

= X²-5X/6 + 1/6 = 0

= 6X² -5X+1 = 0

HENCE,

THE REQUIRED POLYNOMIAL = 6X²-5X+1

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