alpha amd beta are zeroes of x2+2x-1, then find 1\alpha+1\beta
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Given:
- α and β are the zeroes of x²+2x-1
To Find:
- The Value if 1/α +1/β.
Answer:
Let us first simplify 1/α +1/β.
⇒1/α +1/β.
⇒α + β / α β.
We can now see that in numerator sum of roots is there and in denominator product of roots is there.
So , of a quadratic equation of standard form ax²+bx + c = 0 .
- Sum of roots is given by -b/a.
- Product of roots is given by c/a.
⇒-b/a = -2/1 = -2.
⇒c/a = -1/1 = -1.
On putting the respective values,
⇒1/α +1/β = α + β / α β..
⇒1/α +1/β = -2/-1.
⇒1/α +1/β = 2.
Hence the required answer is 2.
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