Question

alpha and 1÷alpha are the zero of quadratic equation 4x^2-2x+k+7 then find the value of k

Answer 1

Answer: alpha and 1/alpha =0 therefore value of x=0 taking this value of x in the  equation 4x^2-2x+k+7 hence (4*0)^2-2*0+k+7=0 ∴0-0+k+7=0  hence k= -7