alpha and beta are 0s of a quadratic polynomial x^2-x-30 the form of a quadratic polynomial whose 0s are 2-alpha and 2-beta
Answers
Answered by
0
hey mate
here is the answer....
Answer:
@ and b are two zeros!
on factorising, x²-x-30
=>x²-x-30=0
=>x²-(6-5)x+30=0
=>x²-6x+5x-30=0
=>x(x-6)+5(x-6)=0
=>(x-6)(x+5)=0
=>x=6 and -5
thus,
=>2-@=2-(-5)
=>2+5=7
--------+++++++----------
=>2-b=2-(6)
=>-4
hence the quadratic polynomial with roots 7 and -4 are
x²-(sum of the roots)x+(product of the roots)
=>x²-(7-4)x+(7*-4)
=>x²-3x+28 (Answer)
Answered by
2
Answer:
P(x)=x²-x-30
α+β=1
αβ=-30
Zeros:2-α,2-β
α+β=2-α+2-β
=4-(α+β)
=4-1=3
αβ=(2-α)(2-β)
=4-2α-2β+αβ
=4-2(α+β)+αβ
=4-2(1)+(-30)
=4-2-30
=-28
Q.poly= x²-3x+28
Hope it helps u.....^_^
Ishwarya12:
Pls mark me as brainliest if it helps u :)
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