Alpha and beta are the roots of y square - 2y-7 is equal to 7 find Alpha square + beta square
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0
y^2-2y-14=0...
Alpha +beta =-b/a
Alpha +beta = 2....
Squaring both side we get....
(Alpha + beta)^2 =4
Alpha square + beta square + 2alpha*beta =4
We know that
Alpha *beta=c/a
So alpha* beta = -14
Put value in eq 1
Alpha square + beta square +2(-14)= 4
Alpha square + beta square = 32
Alpha +beta =-b/a
Alpha +beta = 2....
Squaring both side we get....
(Alpha + beta)^2 =4
Alpha square + beta square + 2alpha*beta =4
We know that
Alpha *beta=c/a
So alpha* beta = -14
Put value in eq 1
Alpha square + beta square +2(-14)= 4
Alpha square + beta square = 32
Answered by
2
y2-2y-7=7
=y2-2y-7-7=0
=y2-2y-14=0
= a=1; b= -2 ; c= -14
= alpha+beta= -b/a
= -(-2)/1
= 2
= alpha * beta=c/a
= -14/1
= -14
[its some what like (a+b)2 formula]
(alpha + beta)2 = alpha2 + beta2 + 2alpha* beta
(alpha + beta)2 - 2 alpha * beta = alpha2 + beta 2
(2)2 - 2(-14)= alpha2 + beta 2('coz we have to find alpha2 + beta2 we keep it one side and substitute the values of alpha + beta and alphabeta on the other side)
alpha 2+ beta2 =4+28
=32
therefore alpha2 + beta2 =32
=y2-2y-7-7=0
=y2-2y-14=0
= a=1; b= -2 ; c= -14
= alpha+beta= -b/a
= -(-2)/1
= 2
= alpha * beta=c/a
= -14/1
= -14
[its some what like (a+b)2 formula]
(alpha + beta)2 = alpha2 + beta2 + 2alpha* beta
(alpha + beta)2 - 2 alpha * beta = alpha2 + beta 2
(2)2 - 2(-14)= alpha2 + beta 2('coz we have to find alpha2 + beta2 we keep it one side and substitute the values of alpha + beta and alphabeta on the other side)
alpha 2+ beta2 =4+28
=32
therefore alpha2 + beta2 =32
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