Question

alpha and beta are the zeroes of polynomial x^2-(k+8)x+3(2k+1). If alpha+beta=alphabeta/3,find value of k

Answer 1

Alpha + beta = - b/a
-[- ( k+8 ) ] / 1
= K+8 .............1)
Alpha× beta = C/a
= 3(2k +1)/1
= 6k + 3 / 1
= 6k+3 .............2)

It is given in the question :-)
Alpha + beta = (alpha × beta ) / 3..................3)

Now subtitute 1 and 2 in 3. :-)

K+8 = (6k+3 )/ 3
K+8 = 2k+1
8-1 = 2k - k
7 = k...........answer .
I hope this helps !!!!!