Question

Alpha and beta are the zeros of p(x) y^2-4y - 21 so find the value of alpha/beta+beta/alpha

Answer 1

Answer:

-58/21

Step-by-step explanation:

Given,

Alpha and beta are zeros of y^2-4y-21=0

Therefore,

Alpha+beta=-(-4) = 4

Alpha.beta= -21

Therefore,

alpha/beta + beta/alpha

= (alpha^2 + beta^2)/alpha.beta

={(alpha+beta)^2 -2alpha.beta}/alpha.beta

={(4)^2 - 2(-21)}/-21

= -58/21