Question

alpha and beta are the zeros of the polynomial x^2 -(x +6) +2(2k -1). Find the value of k if alpha + beta = 1/2 alpha beta (ITS URGENT)

Answer 1

Answer:

Step-by-step explanation:

x^2-(x+6)+2(2k-1)= x^2-x-6+4k-2 =x^2-x+4k-8

Let x^2-x+4k-8 be of the form ax^2+bx+c;a=1,b= -1,c=4k-8

let α+β be the zeroes.

 α+β= -b/a=-(-1)=1

 αβ=c/a=4k-8

Given, α+β=1/2αβ

       So,     1=4k-8

                   4k=9

                 ∴k=9/4