Math, asked by wwwsudeshmohar06, 11 months ago

alpha and beta are the zeros of the polynomial x to the power 2 + 6 X + 2 then find the value of one upon alpha + 1 upon beta​

Answers

Answered by rohitrs0908
1

Answer:

Step-by-step explanation:

x² + 6 x + 2

α + β = (-coefficient of x / coefficient of x²)

α + β =  -6/1 = -6

αβ = (coefficient of constant term / coefficient of x²)

αβ = (2/1) = 2

1/α + 1/β

= (α+β)/αβ

= -6/2

= -3

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