Question

Alpha and beta are the zeros of x^2-3x+2 then find alpha^2+beta^2,4alpha×beta

Answer 1

=x^2-3x+2 = x^2-2x-x+2

=x(x-2)-1(x-2)

=(x-1)(x-2)

as alpha and beta are the zeros for this equation then,

(x-1)(x-2)=0

x=1 , x=2

alpha=1 , beta=2

alpha^2=1^2=1

beta^2=2^2=4

4alpha.beta= 4.1.2=8