Question

Alpha and beta are zeroes of polynomial x2-5x+6 then find value of alpha+beta-3alphabeta

Answer 1

Step-by-step explanation:

x^2-5+6=0

x^2-3x+2x+6=0

x(x-3)+2(x-3)=0

(x+2)(x-3)=0

x=-2,3

alpha + beta- 3alpha beta=

-2+3-3×(-2)×(3)=-2+3+18=19