Question

Alpha and beta are zeroes of x²-x-30 find to form a polynomial whise zeroes are 2-alpha and 2-beta

Answer 1

Hope This helps ....

Answer 2

$x {}^{2} - x - 30$

$x {}^{2} - 6x + 5x - 30$

$x(x - 6) + 5(x - 6)$

$(x - 6)( x + 5)$

x = 6 = beta , x = - 5 = alpha

Another polynomial of

$2 - \alpha \: \: \: and \: \: \: 2 - \beta \: \: is$

2-(-5) , 2-6

$\alpha = 7 \\ \beta = - 4$

$k( {x}^{2} - (\alpha + \beta )x + (\alpha \beta ))$

${x}^{2} - (7 - 4)x + (7 \times - 4)$

${x}^{2} - 2x - 28$