alpha and beta are zeros of polynomial. f(x)=5x(square)-3x-2. then alpha square +beta square
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Let alpha be a and beta be b.
Given a and b are zeros of f(X)=5x^2-3x-2..
Implies
Sum of zeros (a+b)=-(-3/5)
Product of zeros(ab)=-2/5
Now.. using. (a+b)^2-2ab. U will get the required solution by substituting the values..
Given a and b are zeros of f(X)=5x^2-3x-2..
Implies
Sum of zeros (a+b)=-(-3/5)
Product of zeros(ab)=-2/5
Now.. using. (a+b)^2-2ab. U will get the required solution by substituting the values..
Answered by
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Hi there !
f(x) = 5x² - 3x - 2
a = 5
b = -3
c = -2
α and β are zeros of f(x)
sum of zeros = -b/a
α + β = -(-3/5) = 3/5
Product of zeros = c/a
αβ = -2/5
To find :-
α² + β²
α² + β² = (α +β )² - 2αβ
= (3/5)² - 2 × -2/5
= 9/25 + 4/5
= 9/25 + 4×5/25
= 9 + 20 /25
= 29/25
∴ α² + β² = 29/25
f(x) = 5x² - 3x - 2
a = 5
b = -3
c = -2
α and β are zeros of f(x)
sum of zeros = -b/a
α + β = -(-3/5) = 3/5
Product of zeros = c/a
αβ = -2/5
To find :-
α² + β²
α² + β² = (α +β )² - 2αβ
= (3/5)² - 2 × -2/5
= 9/25 + 4/5
= 9/25 + 4×5/25
= 9 + 20 /25
= 29/25
∴ α² + β² = 29/25
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