Math, asked by pinky92149, 10 months ago

alpha and beta are zeros of polynomial Y squared minus 4 Y - 21 then find the value of Alpha square minus b square ​

Answers

Answered by bharat9291
5

Step-by-step explanation:

y ^ 2 - 4y -21

alpha + beta = -b/a = 4

alpha x beta = c/a = -21

now

( alpha + beta ) ^ 2 = ( alpha ) ^ 2 + ( beta ) ^2 + 2* alpha * beta

== ( 4) ^ 2 = ( alpha ) ^ 2 + ( beta ) ^ 2 + 2 * (-21)

( alpha ) ^ 2 + ( beta) ^2 = 58

now

( alpha - beta ) ^ 2 = ( alpha ) ^ 2 + ( beta ) ^ 2 - 2* alpha * beta

( alpha - beta ) ^ 2 = 58 - 2 (-21)

( alpha - beta ) ^ 2 = 100

( alpha - beta ) = 10

now

( alpha ) ^ 2 - ( beta ) ^ 2 = ( alpha + beta ) ( alpha - beta )

= 10 * 4 = 40

Answered by moneshofficial588
0

Step-by-step explanation:

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