Question

Alpha and Bita are the roots of y^2-2y-7=0 find, 1).alpha^3+bita^3

Answer 1

sorry don't know the answer

Answer 2

β³=(α+β)(α²+β²+αβ)----(1)

Answer:

Step-by-step explanation:

If α and β are roots of

y²-2y-7=0 then

αβ=-7

and α+β=2

Now α³+β³=(α+β)(α²+β²-αβ)-------------------(1)

α²+β²=(α+β)²-2αβ

=2*2-2*(-7)

=4+14=18

Putting all values in (1) we get

α³+β³=(2)*(18+7)

=2*25=50