Alpha and Bita are the roots of y^2-2y-7=0 find, 1).alpha^3+bita^3
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β³=(α+β)(α²+β²+αβ)----(1)
Answer:
Step-by-step explanation:
If α and β are roots of
y²-2y-7=0 then
αβ=-7
and α+β=2
Now α³+β³=(α+β)(α²+β²-αβ)-------------------(1)
α²+β²=(α+β)²-2αβ
=2*2-2*(-7)
=4+14=18
Putting all values in (1) we get
α³+β³=(2)*(18+7)
=2*25=50
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