Alpha and1/alpha are the zeroes of 4x^2-2x+(k-4)find the value of k
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Answered by
1
Hey
Here is your answer,
4x^2-2x+(k-4) = 0
Sum of zeroes = -b/a
Alpha + 1/ alpha = 2/4
= 1/2
Product of zeroes = c/a
Alpha x 1/alpha = (k-4)/4
(k-4)/4 = 1
K-4=4
K=4+4
K=8
Hope it helps you!
Here is your answer,
4x^2-2x+(k-4) = 0
Sum of zeroes = -b/a
Alpha + 1/ alpha = 2/4
= 1/2
Product of zeroes = c/a
Alpha x 1/alpha = (k-4)/4
(k-4)/4 = 1
K-4=4
K=4+4
K=8
Hope it helps you!
deepapaul1234le:
Thax its correct
But the sum of zeroes is not needed
Answered by
0
a×1/a=c/a. given that alpha andand 1/alpha are zero of polynomial
a*1/a=k-4/4
1=k-4/4
4=k-4
K=8
a*1/a=k-4/4
1=k-4/4
4=k-4
K=8
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