Question

alpha beta and gamma are the zeros of the polynomial 6 x cube + 3 x square - 5 x + 1 then find the value of Alpha power minus 1 + beta power minus 1 + Gamma power -1

Answer 1

6x^3 + 3x^2 - 5x + 1 = 0

a = 6

b = 3

c = -5

d = 1

Then, αβ + βγ + αγ = c/a = -5/6

Also, αβγ = -d/a = -1/6

$\alpha^{ - 1} + \beta^{ - 1} + \gamma^{ - 1}$

$= \frac{1}{ \alpha } + \frac{1}{ \beta } + \frac{1}{ \gamma }$

$= \frac{ \beta \gamma + \alpha \gamma + \alpha \beta }{ \alpha \beta \gamma }$

$= \frac{ \frac{ - 5}{6} }{ \frac{ - 1}{6} }$

$= 5$

Answer 2

Answer:

Step-by-step explanation:

May help you i hope so