Question

alpha , beta are the roots of ax^2+bx+c =0 [alpha/beta -beta / alpha]^2​

Answer 1

Answer:

al + be =(-b/a) al×be=(c/a)

al - be = √{(al+be)^2-4al.br}=√{(-b/a)^2-4(c/a)}

=√{b^2-4ac)/a

{al/be-be/al}^2={(al^2-be2)/(al.be)}^2={(al+be)(al-be)/(al.be)}^2

Now in this you put values of al+be, al-be and al.be, You will get answer