Question

Alpha beta are the roots of MX square +nx+k=0 then alpha +beta​

Answer 1

Answer:

alpha + beta = -b

a

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Answer 2

Answer:

-n/m

Step-by-step explanation:

Let p(x)= $mx^{2} + nx + k$

Comparing with, $ax^{2} + bx + c$

a=m, b=n, c=k

α+β = -b/a = -n/k

Hope this helps.