alpha ,beta are the roots of the quadratic polynomial p(x)=x^2-(k-6)x+(2k+1). find the value of k, if alpha+beta=alphabeta
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Answered by
144
hi here is ur answer dear...
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hope it helps uh
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Answered by
68
Given :-
x² - ( k - 6 )x + ( 2k + 1 )
alpha + beta = alpha . beta
Sum of roots =



Product of Roots :-




k - 6 = 2k + 1
k - 2k = 1 + 6
- k = 7
k = - 7
x² - ( k - 6 )x + ( 2k + 1 )
alpha + beta = alpha . beta
Sum of roots =
Product of Roots :-
k - 6 = 2k + 1
k - 2k = 1 + 6
- k = 7
k = - 7
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