Math, asked by Vish1777, 1 year ago

alpha ,beta are the roots of the quadratic polynomial p(x)=x^2-(k-6)x+(2k+1). find the value of k, if alpha+beta=alphabeta

Answers

Answered by Anonymous
144
hi here is ur answer dear...
hope it helps uh
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Answered by ALTAF11
68
Given :-

x² - ( k - 6 )x + ( 2k + 1 )

alpha + beta = alpha . beta


Sum of roots =

 \frac{coefficient \: of \: x}{coefficient \: of \:  {x}^{2} }
 \alpha  +  \beta  =  \frac{k - 6}{1}


 \alpha  +  \beta  = k - 6



Product of Roots :-
 \frac{constant \: term}{coefficient \:of \:  {x}^{2}  }


 \alpha  \beta  =  \frac{2k + 1}{1}


 \alpha  \beta  = 2k + 1

 \alpha  +  \beta  =  \alpha  \beta (given)

k - 6 = 2k + 1

k - 2k = 1 + 6

- k = 7

k = - 7
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