ALPHA , BETA ARE THE ROOTS OF THE QUADRATIC POLYNOMIAL p(x)=x2 - (k+6)x +2(2k-1).FIND THE VALUE OF k,IF alpha + beta =1/2 alpha beta
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Let α and β are zeroes of the polynomial = x² - (k + 6)x + 2(2k –1).
On comparing with ax²+bx+c=0
a= 1, b= -( k+6) , c = 2(2k –1)
Sum of zeroes (α+β)= -b/a = -(-(k+6))/1
α+β= (k+6)…………....(1)
Product of zeros(α.β)= c/a = 2(2k –1)/1
α.β= c/a = 4k -2…………(2)
Given: (α+β) = ½(αβ )
(k+6) = ½( 4k -2)
[From eq 1 & 2]
2 (k +6 )= 4k -2
2k +12 = 4k -2
2k -4k = -2 -12
-2k = -14
k = 14/2
k = 7
Hence, the value of k is 7
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