alpha,beta are the zeroes of x²+3x+4 then find the value of alpha²+beta²
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Step-by-step explanation:
alpha beta are the roots of the given equation
Let alpha be m
Let beta be n
Then m^2+n^2=(m+n)^2-2mn
Sum of roots = -b/a=-3/1=-3 for the general equation ax^2+bx+c=0
Product of roots = c/a=4/1=4
=(-3)^2-2(4)=9-8=1
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