Question

alpha, beta are the zeros of polynomial x2-(k+6)x+2(2k-1) then find the value of k if alpha + beta = 1/2 alpha beta

Answer 1

Hey

Here is your answer,

x^2 -(k+6)x + 2(2k-1)=0

Sum of zeroes = -b/a
Alpha + beta = -[-(k+6)]/1
=-(k+6)

Product of zeroes= c/a
Alpha x beta = 2(2k-1)/1
= 2(2k-1)

According to the question,

Alpha + beta = 1/2 x alpha x beta
(k+6)=1/2 x 2(2k-1)
k+6=2k-1
2k-k=6+1
k=7

Hope it helps you!

Answer 2

Heya user..!!

Here is ur answer..!!

___________________________________________________

Answer:

• k = 7

• Step-by-step explanation:

x2-(k+6)x+2(2k-1)

• α + β = - b/a = k+6/1 → k+6

• α  β = c/a = 4k-2/1  → 4k - 2

That's given that :

• Alpha + Beta = 1/2 alpha beta

• ACCORDING TO THIS STATEMENT WE CAN SOLVE IT FURTHER :

(k+6) = ½( 4k -2)

2 (k +6 )= 4k -2

2k +12 = 4k -2

2k -4k = -2 -12

-2k = -14

k = 14/2

k = 7

∴ THE VALUE OF k IS EQUAL'S TO : 7

_________________________________________________________

I Hope this may help u..!!

# Be Brainly..!! #

And keep smiling..!!

:)