Alpha , beta ,gamma are zeros of a cubic polynomial Kx3 - 5x +9 . if alpha 3 +beta3 + gamma3 = 27. Find the value of K
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3α + 3β + 3gama = 27
3 ( α +β + gama) = 27
α + β +gama = 27/ 3 = 9
Now we know that,
α + β + gama = - coefficient of x square / coefficient of x cube
= > 9 = - 0 / K
= >9 K = 0
= > K = 0
hope it will help you..... ☺☺
3 ( α +β + gama) = 27
α + β +gama = 27/ 3 = 9
Now we know that,
α + β + gama = - coefficient of x square / coefficient of x cube
= > 9 = - 0 / K
= >9 K = 0
= > K = 0
hope it will help you..... ☺☺
ploopy5288:
thx
and for u you too the answer is -1
alpha, beta and gamma are raised to power 3
not 3 times
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